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Question #46993

Difficulty: 8/10 | 🟢 Free

The Question

In an Ascomycete fungus, the dikaryotic ascogenous hyphae (n+n) undergo karyogamy to form a diploid zygote (2n = 10). During the subsequent meiosis, a failure in the spindle assembly checkpoint results in the non-disjunction of a single bivalent exclusively during Anaphase I. Assuming Meiosis II proceeds normally, which of the following correctly describes the chromosomal constitution and chromatid state of the four resulting nuclei prior to the post-meiotic mitosis?

Options

  • A.

    Two nuclei will contain 6 chromosomes and two will contain 4 chromosomes; all chromosomes will consist of a single chromatid.

  • B.

    Two nuclei will contain 6 chromosomes and two will contain 4 chromosomes; all chromosomes will consist of two sister chromatids.

  • C.

    Two nuclei will contain 5 chromosomes, one will contain 6, and one will contain 4; all chromosomes will consist of a single chromatid.

  • D.

    Four nuclei will contain 5 chromosomes each, but two nuclei will possess an aberrant DNA content due to malsegregation.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Comparative_Analysis

Sharpen your ability to evaluate multiple scenarios and distinguish between competing potential answers.

Concepts Behind This Question

Phycomycetes_Aseptate_Hyphae|Niche_Overlap_vs_Resource_Partitioning|Primary_Succession_Facilitation

Why This Question Is Tricky

Common Mistakes

Conceptual Pivot: Differentiating the exact ploidy and chromatid outcomes of Meiosis I versus Meiosis II non-disjunction.

A common misconception is confusing the 100% aneuploidy rate of Anaphase I errors (two n+1, two n-1) with the 50% aneuploidy rate of Anaphase II errors (two n, one n+1, one n-1), while also failing to track the transition from dyad (two chromatids) to monad (single chromatid) states.

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Question Information

SubjectBiology
ChapterBiological Classification - Class 11
ConceptPhycomycetes Aseptate Hyphae
Difficulty8
Cognitive Load5
Target Solve Time120 sec
AccessFree