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Question #46958
The Question
Diatoms (Chrysophytes) and eubacteria both undergo cellular division, but their cell boundary structures impose fundamentally different geometric constraints. Which of the following statements correctly contrasts these constraints during cytokinesis?
Options
- A.
Both diatoms and eubacteria rely on mesosome-like membrane invaginations to synthesize their respective siliceous and peptidoglycan cell walls during binary fission.
- B.
The rigid, overlapping siliceous shells of diatoms cause a progressive size reduction in one daughter lineage during successive divisions, whereas bacterial mesosomes guide septum formation without imposing a progressive size constraint.
- C.
The indestructible nature of the diatom cell wall prevents standard cytokinesis, requiring them to divide exclusively via meiotic auxospore formation, unlike the amitotic division of bacteria.
- D.
Bacterial cytokinesis is constrained by a rigid, overlapping peptidoglycan 'soap-box' structure, whereas diatoms utilize flexible siliceous membranes for equal cytoplasmic cleavage.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Evolutionary_Exception
Tackle problems where standard rules evolve or change based on specific environmental constraints.
Concepts Behind This Question
Chrysophytes Silica Wall|Evolutionary Chronology|Abiogenesis vs. Biogenesis
Why This Question Is Tricky
Common Mistakes
Conceptual Pivot: Students often memorize 'soap box' (diatoms) and 'mesosome' (bacteria) as isolated NCERT facts.
This question tests the synthesis of how these physical structures mechanically dictate cell division geometry.
The trap lies in confusing eukaryotic vs. prokaryotic division mechanisms and failing to recognize the unique 'shrinking division' consequence of the indestructible silica wall.
Quick Facts About This Question
Question Information
| Subject | Biology |
| Chapter | Biological Classification - Class 11 |
| Concept | Chrysophytes Silica Wall |
| Difficulty | 8 |
| Cognitive Load | 5 |
| Target Solve Time | 120 sec |
| Access | Free |