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Question #46739
The Question
A cell biologist treats a mammalian secretory cell with Brefeldin A, a chemical agent that disrupts coat protein recruitment, causing the Golgi cisternae to completely fuse back into the Endoplasmic Reticulum (ER). This effectively destroys the cis-trans polarity of the Golgi apparatus. Based on your understanding of the endomembrane system, which of the following will be the most direct and immediate consequence in this cell?
Options
- A.
Direct exocytosis of newly synthesized, unmodified proteins from the rough ER to the plasma membrane.
- B.
Immediate inhibition of peptide bond formation by the 80S ribosomes attached to the rough ER.
- C.
Cessation of glycoprotein formation and intracellular accumulation of unmodified secretory proteins.
- D.
Hyper-accumulation of mature, fully glycosylated proteins at the trans face of the Golgi apparatus.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Regulatory_Failure
Understand how NOT, EXCEPT, and logical constraints are used to manipulate exam results.
Concepts Behind This Question
Golgi Apparatus|COP-II|Endomembrane System Connectivity
Why This Question Is Tricky
Common Mistakes
Conceptual Pivot: Students often memorize that the 'Golgi packages proteins' but fail to grasp the strict, unidirectional dependency of the secretory pathway (ER -> cis-Golgi -> trans-Golgi -> Plasma Membrane).
The trap lies in assuming that if the Golgi is compromised, the ER might take over direct secretion (Option A) or that translation itself stops (Option B).
The key NCERT-aligned realization is that Golgi polarity is an absolute structural requirement for glycoprotein maturation and subsequent exocytosis.
Quick Facts About This Question
Question Information
| Subject | Biology |
| Chapter | Cell – The Unit of Life - Class 11 |
| Concept | Golgi Polarity |
| Difficulty | 8 |
| Cognitive Load | 5 |
| Target Solve Time | 120 sec |
| Access | Free |