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Question #45494

Difficulty: 8/10 | 🟢 Free

The Question

In an angiosperm species exhibiting gametophytic self-incompatibility, a female plant with the genotype S1S2 is pollinated by a male plant with the genotype S2S3. Following successful pollen-pistil interaction and double fertilization, what proportion of the functional megaspores within the ovules of this female plant will possess the S3 allele?

Options

  • A.

    50%, because only the S3 pollen successfully germinates and contributes to the ovule.

  • B.

    25%, due to the independent assortment of alleles during the formation of the embryo sac.

  • C.

    0%, because megaspores are products of maternal meiosis and are formed prior to fertilization.

  • D.

    100%, as the S2 pollen is rejected by the pistil, making S3 the sole genetic contributor to the female gametophyte.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Regulatory_Failure

Understand how NOT, EXCEPT, and logical constraints are used to manipulate exam results.

Concepts Behind This Question

Megasporogenesis|Pollen-Pistil Interaction|Incompatibility Genes

Why This Question Is Tricky

Common Mistakes

Conceptual Pivot: Students frequently conflate the genetic outcome of fertilization (the zygote's genotype) with the structures that precede it.

When presented with a genetic cross, the common trap is to immediately calculate the progeny's genotypes (which would indeed all contain S3 since S2 is rejected) and erroneously apply those ratios to the megaspore, failing to recognize that the megaspore is a strictly maternal, pre-fertilization haploid cell.

Quick Facts About This Question

Question Information

SubjectBiology
ChapterSexual Reproduction in Flowering Plants - Class 12
ConceptMegasporogenesis Symmetry
Difficulty8
Cognitive Load5
Target Solve Time120 sec
AccessFree