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Question #45261

Difficulty: 8/10 | 🟢 Free

The Question

In a mammalian cell culture, a researcher experimentally accelerates the S-phase, causing DNA polymerase activity to significantly outpace the translation of basic amino acid-rich proteins. Which of the following is the most likely chromosomal consequence during the subsequent M-phase, and what is the precise mechanistic reason?

Options

  • A.

    Polyploidy, due to the failure of cytokinesis following improper chromatin condensation.

  • B.

    Aneuploidy, due to mechanical instability of the kinetochore leading to non-disjunction of sister chromatids.

  • C.

    Polyteny, due to repeated cycles of DNA replication without the formation of the 30 nm chromatin fiber.

  • D.

    Aneuploidy, due to the failure of the cell to replicate its entire genome before entering the G2 phase.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Regulatory_Failure

Understand how NOT, EXCEPT, and logical constraints are used to manipulate exam results.

Concepts Behind This Question

Histone Octamer Charge Interaction|Aneuploidy vs Polyploidy|Interphase Duration Paradox

Why This Question Is Tricky

Common Mistakes

Conceptual Pivot: Linking molecular stoichiometry in S-phase to macroscopic chromosomal aberrations.

Students often fail to distinguish the exact mechanical causes of Aneuploidy (segregation failure due to spindle/condensation issues) versus Polyploidy (cytokinesis failure).

The trap relies on the student knowing that histones are synthesized in S-phase and deducing that a lack of histones disrupts condensation, which specifically triggers non-disjunction rather than whole-genome duplication.

Quick Facts About This Question

Question Information

SubjectBiology
ChapterCell Cycle and Cell Division - Class 11
ConceptInterphase Duration Paradox
Difficulty8
Cognitive Load5
Target Solve Time120 sec
AccessFree