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Question #45108

Difficulty: 8/10 | 🟢 Free

The Question

The position of keto-enol equilibrium in cyclic dicarbonyl compounds is dictated by a delicate thermodynamic balance between intramolecular hydrogen bonding, dipole-dipole repulsions, and Baeyer angle strain. Consider the tautomerization of the following compounds in a non-polar solvent (CCl4CCl_4) at 298 K298\text{ K}:

(I) 1,3-Cyclobutanedione (II) 1,2-Cyclopentanedione (III) 1,3-Cyclohexanedione

Which of the following statements correctly identifies the dominant tautomeric form for (I) and (II) along with the primary thermodynamic rationale?

Options

  • A.

    (I) Diketone, as enolization drastically increases Baeyer strain; (II) Enol, to relieve severe dipole-dipole repulsion of adjacent coplanar carbonyls

  • B.

    (I) Enol, to relieve transannular steric strain; (II) Diketone, to minimize Baeyer angle strain

  • C.

    Both (I) and (II) are Enols, driven by the thermodynamic formation of a resonance-stabilized intramolecular hydrogen bond

  • D.

    (I) Diketone, to avoid the antiaromaticity of the enol form; (II) Diketone, as introducing a third sp2sp^2 carbon drastically increases ring strain

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Bond Angle and Strain|Tautomerism Conditions

Why This Question Is Tricky

Common Mistakes

The question tests a 'Chemical Exception' where the standard heuristic '1,3-dicarbonyls exhibit high enol content due to resonance and H-bonding' fails.

Students often overlook that in small rings (like cyclobutane), geometric constraints (Baeyer strain) override electronic stabilization.

Forcing an sp2 carbon (120 degree ideal) into a 90 degree ring creates prohibitive strain.

Conversely, in 1,2-cyclopentanedione, the hidden variable is the severe dipole-dipole repulsion of adjacent coplanar carbonyls, which forces enolization despite it not being a 1,3-dicarbonyl system.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterOrganic Chemistry – Some Basic Principles and Techniques - Class 11 Part 2
ConceptBond Angle and Strain
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree