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Question #45105

Difficulty: 8/10 | 🟢 Free

The Question

Consider the reaction of 1-bromo-3,4-epoxy-2,2-dimethylbutane with one equivalent of sodium methoxide in methanol at elevated temperature: \ce1−bromo−3,4−epoxy−2,2−dimethylbutane+NaOCH3−>[\ceCH3OH][Δ]MajorProduct(P)\ce{1-bromo-3,4-epoxy-2,2-dimethylbutane + NaOCH3 ->[\ce{CH3OH}][\Delta] Major Product (P)} Identify the major product P\mathbf{P}.

Options

  • A.

    2-(methoxymethyl)-3,3-dimethyloxetane

  • B.

    3,4-epoxy-1-methoxy-2,2-dimethylbutane

  • C.

    4-methoxy-3,3-dimethyltetrahydrofuran

  • D.

    4-bromo-1-methoxy-3,3-dimethylbutan-2-ol

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Bond Angle and Strain|Williamson Ether Synthesis Constraints

Why This Question Is Tricky

Common Mistakes

The question tests the limits of the Williamson ether synthesis by pitting a primary alkyl halide against an epoxide.

Students typically memorize that primary halides are ideal for SN2.

However, the 'hidden variable' is the neopentyl-like steric hindrance of the primary bromide, which completely shuts down intermolecular SN2.

The 'chemical exception' is that the thermodynamic strain relief of the epoxide allows it to act as the superior electrophile.

Furthermore, students must resist the trap of forming the thermodynamically more stable 5-membered ring (THF), recognizing that basic epoxide opening is strictly under kinetic control (attack at the less hindered site), followed by a Thorpe-Ingold assisted oxetane formation.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterOrganic Chemistry – Some Basic Principles and Techniques - Class 11 Part 2
ConceptBond Angle and Strain
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree