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Question #45031
The Question
The standard reduction potential of the aqueous couple is at . Upon the addition of excess aqueous ammonia, the complexes and are formed, with overall formation constants and , respectively. The dramatic difference in formation constants is primarily driven by Ligand Field Stabilization Energy (LFSE) compensation. Calculate the standard reduction potential () for the half-cell. Additionally, identify the spin-only magnetic moments () of the oxidized and reduced ammine complexes, respectively. (Given: )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Complex Ion Oxidation States|Electrode Potential Dependencies
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Electrochemistry and Coordination Chemistry.
The 'Hidden Variable' is the oxidation-state dependence of the spectrochemical series.
Students often memorize as a strong-field ligand, erroneously assigning a low-spin state to (, ).
However, only provides sufficient crystal field splitting () for the higher-charged ion.
Furthermore, the problem traps students who fail to recognize that the massive LFSE gain in forming the low-spin complex thermodynamically stabilizes the state, drastically lowering the reduction potential from to .
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Complex Ion Oxidation States |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |