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Question #45031

Difficulty: 8/10 | 🟢 Free

The Question

The standard reduction potential of the aqueous Co3+/Co2+Co^{3+}/Co^{2+} couple is +1.81 V+1.81\text{ V} at 298 K298\text{ K}. Upon the addition of excess aqueous ammonia, the complexes [Co(NH3)6]3+[Co(NH_3)_6]^{3+} and [Co(NH3)6]2+[Co(NH_3)_6]^{2+} are formed, with overall formation constants β6III=1034\beta_6^{III} = 10^{34} and β6II=105\beta_6^{II} = 10^5, respectively. The dramatic difference in formation constants is primarily driven by Ligand Field Stabilization Energy (LFSE) compensation. Calculate the standard reduction potential (E∘E^\circ) for the [Co(NH3)6]3+/[Co(NH3)6]2+[Co(NH_3)_6]^{3+}/[Co(NH_3)_6]^{2+} half-cell. Additionally, identify the spin-only magnetic moments (μeff\mu_{eff}) of the oxidized and reduced ammine complexes, respectively. (Given: 2.303RTF=0.059 V\frac{2.303RT}{F} = 0.059\text{ V})

Options

  • A.

    +0.10 V; 0 BM, 3.87 BM+0.10\text{ V};\ 0\text{ BM},\ 3.87\text{ BM}

  • B.

    +3.52 V; 0 BM, 1.73 BM+3.52\text{ V};\ 0\text{ BM},\ 1.73\text{ BM}

  • C.

    +0.10 V; 0 BM, 1.73 BM+0.10\text{ V};\ 0\text{ BM},\ 1.73\text{ BM}

  • D.

    +3.52 V; 4.90 BM, 3.87 BM+3.52\text{ V};\ 4.90\text{ BM},\ 3.87\text{ BM}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Complex Ion Oxidation States|Electrode Potential Dependencies

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Electrochemistry and Coordination Chemistry.

The 'Hidden Variable' is the oxidation-state dependence of the spectrochemical series.

Students often memorize NH3NH_3 as a strong-field ligand, erroneously assigning a low-spin state to Co2+Co^{2+} (d7d^7, μ=1.73 BM\mu = 1.73\text{ BM}).

However, NH3NH_3 only provides sufficient crystal field splitting (Δo>P\Delta_o > P) for the higher-charged Co3+Co^{3+} ion.

Furthermore, the problem traps students who fail to recognize that the massive LFSE gain in forming the low-spin d6d^6 complex thermodynamically stabilizes the +3+3 state, drastically lowering the reduction potential from +1.81 V+1.81\text{ V} to +0.10 V+0.10\text{ V}.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterRedox Reactions - Class 11 Part 2
ConceptComplex Ion Oxidation States
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree