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Question #45015
The Question
An electrochemical cell is constructed at 298 K using two Nickel half-cells. Compartment A consists of a electrode immersed in a solution containing and . Compartment B consists of a electrode immersed in a solution containing and . The overall formation constants are and . Assume . Determine the spontaneous EMF of the cell, and identify the coordination geometry and hybridization of the nickel complex present in the \textbf{anodic} compartment.
Options
- A.
0.75 V, Square Planar ()
- B.
0.84 V, Square Planar ()
- C.
0.75 V, Tetrahedral ()
- D.
0.84 V, Tetrahedral ()
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Half-Reaction Media Sensitivity|Complex Ion Oxidation States|Valence Bond Theory Hybridization
Why This Question Is Tricky
Common Mistakes
This problem tests the synergy between Electrochemistry and Coordination Chemistry.
The primary trap is calculating the standard EMF ( V) while ignoring the Nernstian concentration shifts, which leads to incorrect option B.
Furthermore, students must correctly identify the anode by comparing the actual oxidation potentials (), not just assuming Compartment A is the anode.
Finally, it tests the application of Valence Bond Theory/Crystal Field Theory: recognizing that the massive thermodynamic stability () in the anodic compartment is driven by the strong field nature of , which forces a transition from the typical (tetrahedral) geometry of weak field complexes to a (square planar) geometry.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Half-Reaction Media Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |