Start Learning Free

Before You Begin

Question #44973

Difficulty: 8/10 | 🟢 Free

The Question

A 100 mL100 \text{ mL} aqueous buffer solution at 298 K298 \text{ K} (pH=5.0\text{pH} = 5.0) contains 1.65 mmol1.65 \text{ mmol} of a native globular protein non-covalently bound to its prosthetic group, Vitamin C (Ascorbic acid, a monoprotic weak acid with pKa=4.0\text{p}K_a = 4.0). To study the prosthetic group, 50 mL50 \text{ mL} of an immiscible organic solvent (1-octanol) is added, and the mixture is vigorously shaken. The low dielectric constant of 1-octanol disrupts the hydrophobic core of the protein, causing complete denaturation and precipitation at the interface, quantitatively releasing the Vitamin C. The released Vitamin C partitions between the aqueous and organic phases. Only the unionized form of Vitamin C (\ceHA\ce{HA}) is soluble in the organic phase, with a distribution coefficient KD=[\ceHA]org[\ceHA]aq=11.0K_D = \frac{[\ce{HA}]_{org}}{[\ce{HA}]_{aq}} = 11.0. Assuming the pH of the aqueous phase remains constant and the volumes are strictly additive, what is the total concentration of Vitamin C (in all its forms) remaining in the aqueous phase at equilibrium?

Options

  • A.

    11.0 mM11.0 \text{ mM}

  • B.

    1.0 mM1.0 \text{ mM}

  • C.

    4.4 mM4.4 \text{ mM}

  • D.

    8.25 mM8.25 \text{ mM}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Protein Denaturation Specificity|Vitamin Solubility Logic

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Biochemistry (Protein Denaturation via Solvent Dielectric Effect) and Physical Chemistry (Nernst Distribution Law with Acid-Base Equilibrium).

The 'Hidden Variable' trap is that students often apply the partition coefficient to the total analytical concentration rather than the specific unionized species (\ceHA\ce{HA}) that actually crosses the phase boundary.

Furthermore, a secondary trap exists where students successfully calculate the concentration of the unionized form (1.0 mM1.0 \text{ mM}) but forget to add the ionized form (\ceA−\ce{A-}) back to determine the total aqueous concentration requested.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterBiomolecules - Class 12
ConceptProtein Denaturation Specificity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree