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Question #44965

Difficulty: 8/10 | 🟢 Free

The Question

Consider the non-standard amino acid 2-amino-3-(4-aminophenyl)propanoic acid (pp-aminophenylalanine) in an aqueous solution at 298 K. The pKapK_a values for its three ionizable groups are 2.0, 4.6, and 9.2. Calculate the isoelectric point (pI) of this amino acid.

Options

  • A.

    6.9

  • B.

    3.3

  • C.

    5.6

  • D.

    5.3

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Amino Acid Zwitterion pH Sensitivity|Carboxylic Acid Strength|Inductive Effect Trends

Why This Question Is Tricky

Common Mistakes

This question targets a common, fatal heuristic used by students: 'If an amino acid has two pKapK_a values below 7, it acts like an acidic amino acid (e.g., Aspartic acid), and the pI is the average of the two lowest values.' Applying this blindly yields a pI of 3.3 (Option B).

The trap exploits the fundamental difference between a neutral acid (0→−10 \rightarrow -1 charge transition, like a side-chain carboxyl group) and a cationic acid (+1→0+1 \rightarrow 0 charge transition, like the anilinium ion here).

Because the pKapK_a of 4.6 belongs to a cationic acid, the molecule transitions from a +1+1 to a 00 charge state at this pH, making 4.6 the lower bound of the zwitterion, not the upper bound.

Students must draw the actual protonation states rather than relying on numerical pattern matching.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterBiomolecules - Class 12
ConceptAmino Acid Zwitterion pH Sensitivity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree