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Question #44931
The Question
Consider the compound , which is 2,4,6-tri-\textit{tert}-butylnitrobenzene. Reaction 1: is treated with excess in dry ether at reflux to yield major product . Reaction 2: is treated with followed by aqueous to yield major product . Identify , , and the correct relationship between the basicity constant () of and aniline.
Options
- A.
= 2,4,6-tri-\textit{tert}-butylaniline; = 2,4,6-tri-\textit{tert}-butylaniline;
- B.
= 2,2',4,4',6,6'-hexa-\textit{tert}-butylazobenzene; = 2,4,6-tri-\textit{tert}-butylaniline;
- C.
= 2,2',4,4',6,6'-hexa-\textit{tert}-butylazobenzene; = 2,4,6-tri-\textit{tert}-butylaniline;
- D.
= 2,4,6-tri-\textit{tert}-butylphenylhydroxylamine; = 2,4,6-tri-\textit{tert}-butylaniline;
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Reduction Selectivity (Sn/HCl vs LiAlH4)|Ortho-Effect in Anilines|Electrophilic Substitution Control
Why This Question Is Tricky
Common Mistakes
This problem tests two major exceptions to standard rules.
First, it traps students who blindly apply the rule that 'LiAlH4 reduces nitrobenzene to azobenzene', ignoring that extreme steric hindrance prevents the necessary bimolecular coupling, leading to the primary amine instead.
Second, it subverts the standard 'Ortho-Effect in Anilines' (which states ortho-anilines are less basic due to hindered solvation) by using a substituent so bulky that Steric Inhibition of Resonance (SIR) forces the amine out-of-plane, localizing the lone pair and drastically increasing basicity.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Amines - Class 12 |
| Concept | Reduction Selectivity (Sn/HCl vs LiAlH4) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |