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Question #44929
The Question
Consider the polyfunctional compound , Ethyl 3,3,5-trimethyl-5-nitro-2-oxohexanoate. is subjected to two different reduction sequences:
Sequence 1: (Major Product) Sequence 2: (Major Product)
Assuming no ester hydrolysis occurs in Sequence 1, identify the major products and .
Options
- A.
= Ethyl 3,3,5,5-tetramethyl-4,5-dihydro-3H-pyrrole-2-carboxylate ; = 5-amino-3,3,5-trimethylhexane-1,2-diol
- B.
= Ethyl 5-amino-3,3,5-trimethyl-2-oxohexanoate ; = (3,3,5,5-tetramethylpyrrolidin-2-yl)methanol
- C.
= Ethyl 3,3,5,5-tetramethyl-4,5-dihydro-3H-pyrrole-2-carboxylate ; = (3,3,5,5-tetramethylpyrrolidin-2-yl)methanol
- D.
= Ethyl 5-amino-3,3,5-trimethylhexanoate ; = 5-amino-3,3,5-trimethylhexane-1,2-diol
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Reduction Selectivity (Sn/HCl vs LiAlH4)|Nucleophilic Acyl Substitution|Esterification Reversibility
Why This Question Is Tricky
Common Mistakes
The question tests chemoselectivity and kinetic vs. thermodynamic control in polyfunctional molecule reductions.
The 'hidden variable' is the relative rate of reduction by LiAlH4.
Students often assume that since LiAlH4 reduces all groups, the amine will form and cyclize just like in the Sn/HCl case, leading to a pyrrolidine derivative (Option C).
However, they fail to account for the fact that ketone reduction by hydride is diffusion-controlled and orders of magnitude faster than nitro reduction.
Thus, the ketone is 'masked' as a secondary alcohol before the amine is even generated, completely preventing the cyclization trap.
Furthermore, the Thorpe-Ingold effect from the gem-dimethyl groups ensures rapid cyclization in Sequence 1.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Amines - Class 12 |
| Concept | Reduction Selectivity (Sn/HCl vs LiAlH4) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |