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Question #44916
The Question
Consider the following aromatic amines in aqueous medium at 298 K: (I) Aniline (II) 2-Methylaniline (III) -Dimethylaniline (IV) -Trimethylaniline
Let and .
Furthermore, compounds III and IV are independently treated with Benzenediazonium chloride (\ce{PhN2+Cl-}) at pH 6 and 273 K. Compound III yields a highly colored azo dye, whereas compound IV yields product Y.
Which of the following correctly identifies the signs of and , and the identity of product Y?
Options
- A.
, , Y is No reaction
- B.
, , Y is 4-(phenyldiazenyl)--trimethylaniline
- C.
, , Y is 5-(phenyldiazenyl)--trimethylaniline
- D.
, , Y is 4-(phenyldiazenyl)--trimethylaniline
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Electrophilic Substitution Control|Inductive Effect Trends|Ortho-Effect in Anilines
Why This Question Is Tricky
Common Mistakes
Students often blindly apply the 'Ortho Effect' as a universal rule that ortho-substituted anilines are always weaker bases.
This question exposes the 'Hidden Variable' of nitrogen substitution.
While primary anilines suffer from Steric Inhibition of Solvation (SIS) leading to decreased basicity, tertiary anilines experience Steric Inhibition of Resonance (SIR), which traps the lone pair on nitrogen and actually increases basicity.
Furthermore, it tests the kinetic consequence of SIR: the loss of the effect deactivates the ring towards weak electrophiles, breaking the assumption that all dialkyl anilines undergo diazonium coupling.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Amines - Class 12 |
| Concept | Electrophilic Substitution Control |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |