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Question #44908
The Question
Consider the reaction of \textit{trans}-dichloridobis(tricyclohexylphosphane)palladium(II) with excess \ce{KSCN} in a suitable solvent at 298 K. The reaction yields a thermodynamically stable, mononuclear square planar complex .
Given:
- \ce{Pd^{2+}} is a soft Lewis acid.
- The Tolman cone angle of tricyclohexylphosphane (\ce{PCy3}) is .
- The \ce{M-N-C} bond angle in N-bonded thiocyanate is , whereas the \ce{M-S-C} bond angle in S-bonded thiocyanate is .
According to IUPAC 2005 recommendations, what is the correct IUPAC name of complex ?
Options
- A.
\textit{trans}-dithiocyanato--bis(tricyclohexylphosphane)palladium(II)
- B.
\textit{trans}-bis(tricyclohexylphosphane)dithiocyanato--palladium(II)
- C.
\textit{trans}-dithiocyanato--bis(tricyclohexylphosphane)palladium(II)
- D.
\textit{trans}-bis(tricyclohexylphosphane)dithiocyanato--palladium(II)
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
IUPAC Nomenclature Priority|Nucleophilic Addition Sterics
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to decouple thermodynamic HSAB rules from steric constraints in coordination chemistry.
Students often blindly apply the HSAB principle (\ce{Pd^{2+}} is soft -> S-bonding) without considering the physical geometry of the binding modes (bent vs linear) and the steric bulk of auxiliary ligands (Tolman cone angle).
Furthermore, it tests a subtle IUPAC nomenclature rule: multiplicative prefixes that are intrinsic to the ligand's name (like 'tri' in tricyclohexylphosphane) MUST be included in alphabetical sorting, unlike prefixes indicating the number of ligands (like 'bis' or 'di').
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Coordination Compounds - Class 12 |
| Concept | IUPAC Nomenclature Priority |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |