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Question #44896
The Question
A non-aqueous electrolytic cell at contains a solution of Uranium salts where the actinoid exists as a mixture of and ions in a molar ratio. A constant current of is passed through the cell for to deposit solid Uranium () at the cathode. Due to ion-pairing and solvent interactions in the non-aqueous medium, the current efficiency for the cathodic deposition is . Assuming both and are reduced to simultaneously at rates proportional to their bulk mole fractions, calculate the mass of Uranium deposited. \n\n(Given: Faraday's constant , Atomic mass of )
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Actinoid Oxidation State Variety|Faraday's First and Second Laws|Standard Electrode Potential Sign Conventions
Why This Question Is Tricky
Common Mistakes
This problem tests the advanced application of Faraday's Laws in non-ideal, mixed-oxidation-state systems.
The primary 'Chemical Exception' is the non-integer -factor.
Students typically memorize integer -factors for standard reductions.
Here, the actinoid's variable oxidation states ( and ) undergo simultaneous competitive reduction.
The 'Key Step' is recognizing that the effective -factor is a weighted average () based on the mole fractions of the ions.
Distractor B traps students who forget to apply the current efficiency.
Distractors C and D trap students who assume only one oxidation state ( or , respectively) is being reduced, ignoring the mixture dynamics.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Actinoid Oxidation State Variety |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |