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Question #44895
The Question
A 50.0 mL aqueous solution contains M and M dissolved in dilute . This solution is titrated with M .
At 298 K, a rapid titration captures only the instantaneous outer-sphere electron transfer reactions, requiring mL of to reach the first persistent pale pink endpoint.
At 350 K, a prolonged titration ensures complete thermodynamic oxidation of all oxidizable species, requiring mL of .
Given that the oxidations of to and to involve inner-sphere mechanisms and bond cleavages that are kinetically frozen during the rapid 298 K titration, calculate the value of .
Options
- A.
36.0 mL
- B.
28.0 mL
- C.
20.0 mL
- D.
8.0 mL
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Actinoid Oxidation State Variety|KMnO₄ Redox pH Dependency|Variable Oxidation State Stability
Why This Question Is Tricky
Common Mistakes
This problem tests the critical distinction between thermodynamic feasibility and kinetic viability in redox titrations.
Students often blindly apply the n-factor to all oxidizable species present, ignoring mechanistic barriers.
The formation of the actinyl ion () requires the creation of strong U=O bonds (inner-sphere oxygen transfer), which has a high activation energy and is kinetically sluggish at room temperature.
Similarly, oxalate oxidation requires C-C bond cleavage.
By explicitly stating the kinetic freeze, the problem forces the student to selectively apply stoichiometry based on the reaction mechanism at different temperatures, while also avoiding the stoichiometric trap of missing the oxalate ions contributed by the uranium salt.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Actinoid Oxidation State Variety |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |