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Question #44875
The Question
Transition metals in their highest oxidation states exhibit unique optical and chemical properties governed by charge transfer and relativistic effects. Which of the following statements regarding these high oxidation state species is \textbf{INCORRECT}?
Options
- A.
\ce{MnO4^-} and \ce{Cr2O7^{2-}} are intensely colored due to Laporte-allowed Ligand-to-Metal Charge Transfer (LMCT).
- B.
The LMCT energy gap follows the order \ce{MnO4^-} < \ce{TcO4^-} < \ce{ReO4^-}, rendering \ce{ReO4^-} colorless.
- C.
5d high oxidation state fluorides like \ce{PtF6} are stabilized by d-orbital contraction and relativistic effects.
- D.
\ce{PtF6} is a colorless, diamagnetic complex due to the extreme electronegativity of fluorine.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Color and Charge Transfer|d-orbital contraction|Stability of High O.S. Fluorides/Oxides
Why This Question Is Tricky
Common Mistakes
Students often falsely conflate high oxidation states with a d0 configuration and subsequently assume that d0 species must be colorless.
While KMnO4 breaks the 'd0 is colorless' rule via LMCT, PtF6 breaks the 'high O.S. means d0' assumption.
Platinum (Group 10) in the +6 oxidation state retains a d4 configuration.
Furthermore, the question tests the understanding that the stability of extreme oxidation states in the 5d series is driven by relativistic effects and d-orbital contraction, which students frequently misinterpret as a reason for colorlessness rather than enhanced covalent bonding.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Color and Charge Transfer |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |