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Question #44857
The Question
Consider the following reaction sequences starting with toluene (\ce{C6H5CH3}):
Sequence I: \ce{C6H5CH3} (Major)
Sequence II: \ce{C6H5CH3} (Major)
Assume is the recovered organic substrate if no oxidation occurs. Identify the major products and .
Options
- A.
= 3-Nitrobenzaldehyde, = 1-Methyl-4-nitrobenzene
- B.
= 3-Nitrobenzaldehyde, = 3-Nitrobenzoic acid
- C.
= 4-Nitrobenzaldehyde, = 1-Methyl-4-nitrobenzene
- D.
= 1-Methyl-4-nitrobenzene, = 3-Nitrobenzaldehyde
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Variable Oxidation State Stability|Stability of High O.S. Fluorides/Oxides|d-orbital contraction
Why This Question Is Tricky
Common Mistakes
This question tests the student's understanding of periodic trends in oxidation state stability for transition metals versus p-block elements.
A common trap is misapplying the 'Inert Pair Effect' to the d-block, leading students to assume that heavier 5d elements (like W) are less stable in high oxidation states and thus stronger oxidants than 3d elements (like Cr).
If a student falls for this, they will incorrectly assume \ce{WO2Cl2} is a super-oxidant that oxidizes toluene to benzoic acid, leading them to choose the distractor containing 3-Nitrobenzoic acid.
It also rigorously tests Electrophilic Aromatic Substitution (EAS) regioselectivity.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Variable Oxidation State Stability |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |