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Question #44855

Difficulty: 8/10 | 🟢 Free

The Question

A 3d transition metal MM exhibits a positive standard reduction potential E∘(M2+/M)=+0.34 VE^\circ(M^{2+}/M) = +0.34\text{ V} at 298 K298\text{ K} because its hydration enthalpy fails to compensate for the sum of its atomization and ionization enthalpies. When an aqueous solution of M2+M^{2+} is treated with excess KCN(aq)KCN(aq), a soluble coordination complex X\mathbf{X} and a toxic gas Y\mathbf{Y} are formed. Separately, when M2+(aq)M^{2+}(aq) is treated with excess KI(aq)KI(aq), a precipitate Z\mathbf{Z} and a brown solution containing species W\mathbf{W} are formed.

Determine the value of the expression: (p×r)+s−q(p \times r) + s - q Where: pp = Coordination number of the central metal in complex X\mathbf{X} qq = Number of unpaired electrons in the central metal of complex X\mathbf{X} rr = Oxidation state of MM in precipitate Z\mathbf{Z} ss = Atomicity (total number of atoms per molecule) of gas Y\mathbf{Y}

Options

  • A.

    6

  • B.

    8

  • C.

    10

  • D.

    12

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Variable Oxidation State Stability|Electrode Potential Dependencies|Standard Electrode Potential Sign Conventions

Why This Question Is Tricky

Common Mistakes

The question tests the 'Hidden Oxidation State' trap and the thermodynamic anomalies of the 3d series.

Students often assume Cu2+Cu^{2+} forms simple substitution complexes like [Cu(CN)4]2−[Cu(CN)_4]^{2-} or precipitates as CuI2CuI_2.

However, CN−CN^- and I−I^- act as reducing agents, driving Cu2+Cu^{2+} to Cu+Cu^+ due to the extreme stability of the resulting Cu+Cu^+ species (high formation constant of [Cu(CN)4]3−[Cu(CN)_4]^{3-} and high lattice energy of CuICuI).

The positive E∘E^\circ context serves as the initial identifier, reinforcing the Born-Haber cycle exception where hydration energy cannot overcome atomization and ionization energies.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterD and F Block Elements - Class 12
ConceptVariable Oxidation State Stability
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree