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Question #44848
The Question
The electrochemical reduction of an organic reactant \ce{R} occurs at a catalytic electrode of area in a cell of volume at a constant applied potential. The rate of disappearance of \ce{R} in the bulk solution is given by . The reaction proceeds via the initial reversible adsorption of \ce{R} onto the electrode surface, followed by a rate-determining electron transfer step. The enthalpy of adsorption is ().
Under Condition I (low ), the surface coverage of \ce{R} follows the Henry adsorption isotherm. The apparent rate constant is . Under Condition II (high ), the electrode surface is completely saturated with \ce{R}. The apparent rate constant is .
Which of the following correctly identifies the units of and , and the relationship between the apparent activation energy () and the true activation energy of the electron transfer step () under Condition I?
Options
- A.
: , : ,
- B.
: , : ,
- C.
: , : ,
- D.
: , : ,
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Units of Rate Constant (k)|Activation Energy Trap|Electrode Potential Dependencies
Why This Question Is Tricky
Common Mistakes
The problem tests the dimensional shift of the apparent rate constant when a heterogeneous catalytic reaction transitions from a first-order regime (Henry's adsorption at low concentration) to a zero-order regime (surface saturation at high concentration).
Students often mistakenly assign heterogeneous rate constant units () to bulk rate equations or assume has fixed units regardless of the reaction order.
Furthermore, it tests the derivation of apparent activation energy for a reaction with a pre-equilibrium step.
Because adsorption is exothermic (), the apparent activation energy is the sum of the true activation energy and the enthalpy of adsorption ().
A common trap is incorrectly subtracting due to confusion over its negative sign.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Kinetics - Class 12 |
| Concept | Units of Rate Constant (k) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |