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Question #44848

Difficulty: 8/10 | 🟢 Free

The Question

The electrochemical reduction of an organic reactant \ce{R} occurs at a catalytic electrode of area AA in a cell of volume VV at a constant applied potential. The rate of disappearance of \ce{R} in the bulk solution is given by r=−d[\ceR]dt=kapp[\ceR]nr = -\frac{d[\ce{R}]}{dt} = k_{app} [\ce{R}]^n. The reaction proceeds via the initial reversible adsorption of \ce{R} onto the electrode surface, followed by a rate-determining electron transfer step. The enthalpy of adsorption is ΔHads\Delta H_{ads} (ΔHads<0\Delta H_{ads} < 0).

Under Condition I (low [\ceR][\ce{R}]), the surface coverage of \ce{R} follows the Henry adsorption isotherm. The apparent rate constant is kIk_I. Under Condition II (high [\ceR][\ce{R}]), the electrode surface is completely saturated with \ce{R}. The apparent rate constant is kIIk_{II}.

Which of the following correctly identifies the units of kIk_I and kIIk_{II}, and the relationship between the apparent activation energy (Ea,appE_{a,app}) and the true activation energy of the electron transfer step (Ea,trueE_{a,true}) under Condition I?

Options

  • A.

    kIk_I: s−1\text{s}^{-1}, kIIk_{II}: M s−1\text{M s}^{-1}, Ea,app=Ea,true+ΔHadsE_{a,app} = E_{a,true} + \Delta H_{ads}

  • B.

    kIk_I: cm s−1\text{cm s}^{-1}, kIIk_{II}: mol cm−2s−1\text{mol cm}^{-2} \text{s}^{-1}, Ea,app=Ea,true+ΔHadsE_{a,app} = E_{a,true} + \Delta H_{ads}

  • C.

    kIk_I: s−1\text{s}^{-1}, kIIk_{II}: M s−1\text{M s}^{-1}, Ea,app=Ea,true−ΔHadsE_{a,app} = E_{a,true} - \Delta H_{ads}

  • D.

    kIk_I: M s−1\text{M s}^{-1}, kIIk_{II}: s−1\text{s}^{-1}, Ea,app=Ea,true−ΔHadsE_{a,app} = E_{a,true} - \Delta H_{ads}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Units of Rate Constant (k)|Activation Energy Trap|Electrode Potential Dependencies

Why This Question Is Tricky

Common Mistakes

The problem tests the dimensional shift of the apparent rate constant kappk_{app} when a heterogeneous catalytic reaction transitions from a first-order regime (Henry's adsorption at low concentration) to a zero-order regime (surface saturation at high concentration).

Students often mistakenly assign heterogeneous rate constant units (cm s−1\text{cm s}^{-1}) to bulk rate equations or assume kk has fixed units regardless of the reaction order.

Furthermore, it tests the derivation of apparent activation energy for a reaction with a pre-equilibrium step.

Because adsorption is exothermic (ΔHads<0\Delta H_{ads} < 0), the apparent activation energy is the sum of the true activation energy and the enthalpy of adsorption (Ea,app=Ea,true+ΔHadsE_{a,app} = E_{a,true} + \Delta H_{ads}).

A common trap is incorrectly subtracting ΔHads\Delta H_{ads} due to confusion over its negative sign.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptUnits of Rate Constant (k)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree