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Question #44841

Difficulty: 8/10 | 🟢 Free

The Question

A kinetic study of the electrophilic monobromination of a series of substituted N,NN,N-dimethylanilines (\ceXC6H4NMe2\ce{XC6H4NMe2}) is conducted in glacial acetic acid at 298 K. The relative rate constants (kXk_X) are measured, and a Hammett plot of log⁡(kX/kH)\log(k_X/k_H) versus the Brown-Okamoto substituent constants (σ+\sigma^+) is constructed. The \textit{meta} and \textit{para} substituted derivatives exhibit an excellent linear correlation with a slope of ρ\rho. Which of the following accurately describes the sign of ρ\rho and the graphical position of the \textit{ortho}-methyl derivative (\ceX=o−\ceCH3\ce{X} = o-\ce{CH3}) relative to this linear fit?

Options

  • A.

    ρ<0\rho < 0; the o−\ceCH3o-\ce{CH3} point lies significantly below the line due to Steric Inhibition of Resonance.

  • B.

    ρ<0\rho < 0; the o−\ceCH3o-\ce{CH3} point lies significantly above the line due to the enhanced +I+I proximity effect.

  • C.

    ρ>0\rho > 0; the o−\ceCH3o-\ce{CH3} point lies significantly below the line due to Steric Inhibition of Protonation.

  • D.

    ρ>0\rho > 0; the o−\ceCH3o-\ce{CH3} point lies on the line because σ+\sigma^+ inherently accounts for all electronic effects.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Graphical Slopes Analysis|Ortho-Effect in Anilines|Electrophilic Substitution Control

Why This Question Is Tricky

Common Mistakes

The problem tests the boundary conditions of the Hammett equation and the physical reality of the 'Ortho-Effect'.

Students often blindly apply the linear equation log⁡(k/k0)=ρσ+\log(k/k_0) = \rho\sigma^+ to all isomers, expecting a uniform slope.

The hidden variable here is Steric Inhibition of Resonance (SIR).

While a methyl group is electronically activating, placing it \textit{ortho} to a bulky −\ceNMe2-\ce{NMe2} group forces the nitrogen lone pair out of conjugation with the aromatic π\pi-system.

This decoupling of the electronic +M+M effect drastically lowers the reaction rate, causing a severe downward deviation in the kinetic plot.

It forces the student to differentiate between pure electronic parameters and stereoelectronic destabilization.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptGraphical Slopes Analysis
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree