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Question #44833
The Question
Consider the hydrolysis of an ester catalyzed by a typical mesophilic enzyme (optimum temperature K). At K, the reaction proceeds with an initial rate mol L s. The temperature coefficient is determined to be in the range of K to K. A theoretical kineticist calculates the expected rate at K using the rule. Assuming the uncatalyzed reaction rate is negligible, what are the values of the calculated rate () and the experimentally observed rate () at K, respectively?
Options
- A.
mol L s and
- B.
mol L s and mol L s
- C.
mol L s and
- D.
mol L s and mol L s
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Temperature Coefficient (Q10)|Enzyme Specificity 'Lock and Key'
Why This Question Is Tricky
Common Mistakes
This problem tests the boundary conditions of mathematical models in physical chemistry.
Students often blindly apply the Arrhenius equation or the temperature coefficient rule to calculate reaction rates at elevated temperatures.
The 'Hidden Variable' here is the physical integrity of the catalyst itself.
Because the catalyst is a protein (enzyme) with a specific optimum temperature ( K), extrapolating the kinetic model to K ignores the thermal denaturation of the enzyme.
The trap distinguishes students who merely plug numbers into formulas from those who understand the physical and biochemical reality of the reaction system.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Kinetics - Class 12 |
| Concept | Temperature Coefficient (Q10) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |