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Question #44805

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following electrochemical concentration cell with transference at 298 K298 \text{ K}:

\ceAg(s)∣AgNO3(aq,C2)∣∣AgNO3(aq,C1)∣Ag(s)\ce{Ag(s) | AgNO3 (aq, C_2) || AgNO3 (aq, C_1) | Ag(s)}

Initially, the concentrations in both half-cells are C1=C2=0.10 MC_1 = C_2 = 0.10 \text{ M}. The anodic compartment (C2C_2) is subjected to a controlled photochemical process that causes the zero-order reduction of \ceAg+\ce{Ag+} to \ceAg(s)\ce{Ag(s)} with a rate constant k=1.0×10−3 mol L−1 s−1k = 1.0 \times 10^{-3} \text{ mol L}^{-1} \text{ s}^{-1}.

Given that the transport number of the nitrate ion is t−=0.60t_- = 0.60 and assuming ideal behavior, calculate the rate of change of the cell potential, dEcelldt\frac{dE_{\text{cell}}}{dt}, at t=50 st = 50 \text{ s}.

[Use RTF=25 mV\frac{RT}{F} = 25 \text{ mV}]

Options

  • A.

    0.60 mV s−10.60 \text{ mV s}^{-1}

  • B.

    0.50 mV s−10.50 \text{ mV s}^{-1}

  • C.

    0.40 mV s−10.40 \text{ mV s}^{-1}

  • D.

    0.30 mV s−10.30 \text{ mV s}^{-1}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Zero Order Rate Integration|Liquid Junction Potential|Nernst Equation Concentration Dependence

Why This Question Is Tricky

Common Mistakes

This problem tests the synthesis of chemical kinetics and advanced electrochemical thermodynamics.

The primary trap is twofold: First, students often conflate linear concentration decay (zero-order kinetics) with linear voltage decay, failing to apply the nested chain rule to the logarithmic Nernst equation.

Second, the 'Hidden Variable' is the Liquid Junction Potential (EljE_{\text{lj}}).

In a concentration cell with transference, the measured potential is not just the Nernst potential; it is scaled by a factor of 2t−2t_- due to the unequal mobilities of the ions across the junction.

Ignoring EljE_{\text{lj}} leads to Option B, while misapplying the transport numbers leads to Option C.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptZero Order Rate Integration
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree