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Question #44784

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The Question

For a standard H2−O2H_2-O_2 fuel cell operating at 1 bar1\text{ bar}, the standard molar entropies of H2(g)H_2(g), O2(g)O_2(g), and H2O(l)H_2O(l) are 130.6130.6, 205.0205.0, and 69.9 J K−1 mol−169.9\text{ J K}^{-1}\text{ mol}^{-1} respectively. The standard enthalpy of formation of H2O(l)H_2O(l) is −285.8 kJ mol−1-285.8\text{ kJ mol}^{-1}. Assuming ΔH∘\Delta H^\circ and ΔS∘\Delta S^\circ are independent of temperature, which of the following represents the temperature coefficient of the cell (∂E∘∂T)P\left(\frac{\partial E^\circ}{\partial T}\right)_P and the theoretical maximum electrical work obtainable from 1 mole1\text{ mole} of H2(g)H_2(g) at 398 K398\text{ K}? (Given: F=96500 C mol−1F = 96500\text{ C mol}^{-1})

Options

  • A.

    −8.46×10−4 V K−1-8.46 \times 10^{-4}\text{ V K}^{-1} and 220.8 kJ220.8\text{ kJ}

  • B.

    −1.38×10−3 V K−1-1.38 \times 10^{-3}\text{ V K}^{-1} and 180.1 kJ180.1\text{ kJ}

  • C.

    +8.46×10−4 V K−1+8.46 \times 10^{-4}\text{ V K}^{-1} and 350.7 kJ350.7\text{ kJ}

  • D.

    −1.69×10−3 V K−1-1.69 \times 10^{-3}\text{ V K}^{-1} and 220.8 kJ220.8\text{ kJ}

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Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Electrode Potential Dependencies|Fuel Cell Efficiency|Temperature Coefficient (Q10)

Why This Question Is Tricky

Common Mistakes

The problem tests the thermodynamic dependency of fuel cell potential on temperature.

Students often assume that higher temperatures increase the efficiency or work output of a cell due to increased kinetic energy.

However, for a hydrogen-oxygen fuel cell, the reaction is exothermic and involves a decrease in gaseous moles, leading to a negative ΔS∘\Delta S^\circ.

Consequently, the temperature coefficient (∂E∘∂T)P\left(\frac{\partial E^\circ}{\partial T}\right)_P is negative, meaning the cell potential and maximum electrical work (−ΔG∘-\Delta G^\circ) actually decrease at higher temperatures.

The trap options exploit errors in stoichiometry (forgetting the 1/21/2 coefficient for O2O_2), misidentifying n=1n=1, or assuming a positive entropy change.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterElectrochemistry - Class 12
ConceptElectrode Potential Dependencies
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree