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Question #44775

Difficulty: 8/10 | 🟢 Free

The Question

An iron pipeline is exposed to a corrosive aqueous medium at 298 K298\text{ K}. The medium is buffered at pH=8.0\text{pH} = 8.0 and contains a total dissolved Cr(VI) concentration of 0.1 M0.1\text{ M} (i.e., [\ceCrO42−]+2[\ceCr2O72−]=0.1 M[\ce{CrO4^{2-}}] + 2[\ce{Cr2O7^{2-}}] = 0.1\text{ M}). The concentration of \ceCr3+\ce{Cr^{3+}} is 10−2 M10^{-2}\text{ M} and \ceFe2+\ce{Fe^{2+}} is 10−3 M10^{-3}\text{ M}.

Given the following standard reduction potentials and equilibrium constant: E\ceCr2O72−/Cr3+∘=+1.33 VE^\circ_{\ce{Cr2O7^{2-}/Cr^{3+}}} = +1.33\text{ V} E\ceFe2+/Fe∘=−0.44 VE^\circ_{\ce{Fe^{2+}/Fe}} = -0.44\text{ V} \ceCr2O72−(aq)+H2O(l)⇌2CrO42−(aq)+2H+(aq)\ce{Cr2O7^{2-}(aq) + H2O(l) \rightleftharpoons 2CrO4^{2-}(aq) + 2H+(aq)}, Keq=10−14K_{eq} = 10^{-14}

Assume 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06\text{ V}.

Calculate the cell potential (EcellE_{cell}) for the oxidation of iron by the Cr(VI) species in this medium.

Options

  • A.

    +0.74 V+0.74\text{ V}

  • B.

    +0.77 V+0.77\text{ V}

  • C.

    +0.21 V+0.21\text{ V}

  • D.

    +1.78 V+1.78\text{ V}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Corrosion as Electrochemical Process|Dichromate-Chromate Equilibrium|Electrode Potential Dependencies

Why This Question Is Tricky

Common Mistakes

This problem tests the coupling of chemical equilibrium with electrochemistry.

A common trap is assuming the total Cr(VI) concentration can be directly plugged into the Nernst equation as [\ceCr2O72−][\ce{Cr2O7^{2-}}], ignoring the pH-dependent shift of the dichromate-chromate equilibrium (Le Chatelier's Principle).

At pH 8, Cr(VI) exists predominantly as \ceCrO42−\ce{CrO4^{2-}}, drastically lowering the active [\ceCr2O72−][\ce{Cr2O7^{2-}}] to 10−4 M10^{-4}\text{ M}.

Failing to account for this hidden variable leads to an incorrect reduction potential (Option B).

Furthermore, students must correctly apply the 14th power of [\ceH+][\ce{H+}] in the Nernst equation, which heavily penalizes standard condition assumptions (Option D).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterElectrochemistry - Class 12
ConceptCorrosion as Electrochemical Process
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree