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Question #44755
The Question
A solution is prepared by dissolving of a salt \ce{MCl2} (Molar mass = ) in of a solvent (Molar mass = ). The vapor pressure of pure solvent at is , and the vapor pressure of the solution is . Assume the volume of the solution is exactly .
The standard reduction potential is . The solvent undergoes reduction at the cathode at a constant potential of to evolve \ce{H2} gas.
If this solution is electrolyzed at using inert electrodes, what is the primary cathodic product and the actual reduction potential of the \ce{M^{2+}/M} couple in this solution?
(Given: , )
Options
- A.
\ce{H2} gas is evolved;
- B.
Metal \ce{M} is deposited;
- C.
Metal \ce{M} is deposited;
- D.
\ce{H2} gas is evolved;
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Electrolysis Product Prediction|Degree of Dissociation/Association|Vapor Pressure Lowering (Mole Fraction)
Why This Question Is Tricky
Common Mistakes
This problem tests the integration of Colligative Properties with Electrochemistry, specifically targeting the 'Degree of Dissociation' trap.
Students typically assume complete dissociation () for salts like \ce{MCl2}, which would yield and .
Since , this leads to the incorrect prediction that Metal \ce{M} deposits (Option B).
By forcing the derivation of from vapor pressure data, the true is found to be much lower due to solvent dielectric effects or ion pairing.
This drops the metal's reduction potential below that of the solvent, fundamentally changing the major electrolysis product.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Electrochemistry - Class 12 |
| Concept | Electrolysis Product Prediction |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |