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Question #44735
The Question
An aqueous solution of is treated with excess to form a thermodynamically stable square planar complex ion, . The ligand in exhibits linkage isomerism but coordinates predominantly through its softer donor atom. The overall formation constant () of is .
A half-cell is constructed by dipping a Palladium rod into a solution initially containing and at .
Given: , .
Identify the correct IUPAC name of the complex ion and the reduction potential () of this half-cell.
Options
- A.
tetrathiocyanato--palladate(II) ion;
- B.
tetrathiocyanato--palladate(II) ion;
- C.
tetrathiocyanato--palladate(II) ion;
- D.
tetrathiocyanato--palladate(II) ion;
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Nernst Equation Concentration Dependence|Werner’s Theory Postulates|Ambidentate Linkage Isomerism
Why This Question Is Tricky
Common Mistakes
This problem integrates Coordination Chemistry (HSAB theory and linkage isomerism) with Electrochemistry (Nernst equation coupled to complexation equilibria).
The 'Hidden Variable' is the drastic reduction in free metal ion concentration due to the high formation constant ().
Students often fall into three traps: 1) Failing to identify as a soft acid, leading to the incorrect isomer. 2) Forgetting to subtract the stoichiometrically consumed ligand from the initial concentration, which skews the free and subsequently the free . 3) Confusing the non-standard half-cell potential () with the standard reduction potential of the complex ().
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Electrochemistry - Class 12 |
| Concept | Nernst Equation Concentration Dependence |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |