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Question #44727

Difficulty: 8/10 | 🟢 Free

The Question

An aqueous solution is prepared by dissolving 2.665 g2.665 \text{ g} of a dark green coordination compound with the empirical formula \ceCrCl3.6H2O\ce{CrCl3.6H2O} (Molar mass = 266.5 g mol−1266.5 \text{ g mol}^{-1}) in 100 g100 \text{ g} of water. The freezing point of this solution is −0.372∘C-0.372^\circ\text{C} (KfK_f for water = 1.86 K kg mol−11.86 \text{ K kg mol}^{-1}). Assume 100%100\% ionization of the complex.

When 2.665 g2.665 \text{ g} of this complex is treated with excess \ceAgNO3(aq)\ce{AgNO3(aq)}, x gx \text{ g} of a white precipitate is formed.

When another 2.665 g2.665 \text{ g} sample of the complex is kept over concentrated \ceH2SO4\ce{H2SO4} in a desiccator, it loses y gy \text{ g} of its mass.

Let zz be the total number of stereoisomers possible for the complex cation.

What are the values of xx, yy, and zz? (Molar mass of \ceAgCl=143.5 g mol−1\ce{AgCl} = 143.5 \text{ g mol}^{-1})

Options

  • A.

    x=1.435x = 1.435, y=0.36y = 0.36, z=2z = 2

  • B.

    x=2.870x = 2.870, y=0.18y = 0.18, z=1z = 1

  • C.

    x=4.305x = 4.305, y=0.00y = 0.00, z=1z = 1

  • D.

    x=1.435x = 1.435, y=0.36y = 0.36, z=3z = 3

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Molecular Mass Abnormalities|Hydrate and Ionization Isomerism|Crystal Field Splitting (Octahedral)

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Colligative Properties and Coordination Chemistry (Hydrate Isomerism).

Students often blindly calculate the van't Hoff factor assuming simple salts, or assume the empirical formula \ceCrCl3.6H2O\ce{CrCl3.6H2O} implies i=4i=4.

The trap requires deducing the exact coordination sphere \ce[Cr(H2O)4Cl2]Cl.2H2O\ce{[Cr(H2O)4Cl2]Cl.2H2O} from the freezing point depression.

A secondary stereochemical trap exists: students frequently assume the \textit{cis} isomer of any octahedral complex is optically active, confusing \ceMA4B2\ce{MA4B2} with \ceM(AA)2B2\ce{M(AA)2B2}, which would incorrectly lead to z=3z=3.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSolutions - Class 12
ConceptMolecular Mass Abnormalities
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree