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Question #44703
The Question
The gas-phase photochemical decomposition of ozone is represented by the overall reaction: .
The reaction proceeds via the following mechanism: Step 1: (Fast initiation) Step 2: (Slow, Rate Determining Step)
A photon of energy strikes a stationary molecule, causing the dissociation in Step 1. The bond dissociation energy for is .
Assuming the intermediate generated in Step 1 directly participates in the RDS without any collisional energy loss, what is the De Broglie wavelength of the particle?
(Let be the mass of a single oxygen atom. Assume non-relativistic mechanics and that the excess energy is entirely converted into the translational kinetic energy of the products in Step 1).
Options
- A.
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Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
De Broglie Wavelength Logic|Rate Law Derivation from Mechanism|Stoichiometric Coefficient Division
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Quantum Mechanics, Conservation Laws, and Chemical Kinetics.
The 'Hidden Variable' is the conservation of momentum during the elementary photochemical initiation step.
Students often fall into the 'Stoichiometric Trap' by looking at the overall reaction () and erroneously dividing the excess energy by 2 or 3 to find the kinetic energy of the intermediate.
Alternatively, they may assume all excess energy goes to the lighter atom.
By forcing the student to isolate the elementary Step 1 and apply physics principles (equal momentum, unequal kinetic energy partition based on mass ratio vs ), the question bypasses rote memorization of kinetic formulas and tests true conceptual depth.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Structure of Atom - Class 11 Part 1 |
| Concept | De Broglie Wavelength Logic |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |