Start Learning Free

Before You Begin

Question #44702

Difficulty: 8/10 | 🟢 Free

The Question

A stationary radioactive nucleus \ceZAX\ce{^{A}_{Z}X} undergoes α\alpha-decay to form \ceZ−2A−4Y\ce{^{A-4}_{Z-2}Y}, releasing a total energy QQ. The rest mass of the α\alpha-particle is mαm_\alpha. A student calculates the de Broglie wavelength of the emitted α\alpha-particle using classical mechanics (λclass\lambda_{class}). However, due to the high energy of the decay, relativistic effects must be considered to find the true wavelength (λrel\lambda_{rel}). Assuming the daughter nucleus is non-relativistic, which of the following expressions correctly represents the ratio λrelλclass\frac{\lambda_{rel}}{\lambda_{class}}? (Assume cc is the speed of light in vacuum).

Options

  • A.

    (1+(A−4)Q2Amαc2)−1/2\left( 1 + \frac{(A-4)Q}{2 A m_\alpha c^2} \right)^{-1/2}

  • B.

    (1+(A−4)QAmαc2)−1/2\left( 1 + \frac{(A-4)Q}{A m_\alpha c^2} \right)^{-1/2}

  • C.

    (1+AQ2(A−4)mαc2)−1/2\left( 1 + \frac{A Q}{2 (A-4) m_\alpha c^2} \right)^{-1/2}

  • D.

    (1−(A−4)Q2Amαc2)1/2\left( 1 - \frac{(A-4)Q}{2 A m_\alpha c^2} \right)^{1/2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

De Broglie Wavelength Logic|Radioactive Decay as Kinetics

Why This Question Is Tricky

Common Mistakes

This problem tests a critical 'Hidden Variable' trap: Students habitually use the classical momentum equation p=2mKp = \sqrt{2mK} for all particles unless explicitly told it is a photon or a high-energy electron.

For α\alpha-particles emitted in radioactive decay (energies ~4-9 MeV), the velocity is a significant fraction of cc (~0.05c).

While classical mechanics provides a close approximation, exact analytical precision requires the relativistic mass-energy equivalence.

The trap lies in failing to use the relativistic invariant E2=(pc)2+(m0c2)2E^2 = (pc)^2 + (m_0 c^2)^2 and incorrectly assuming λrel=λclass\lambda_{rel} = \lambda_{class}, or misapplying the Q-value distribution Kα=A−4AQK_\alpha = \frac{A-4}{A}Q.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterStructure of Atom - Class 11 Part 1
ConceptDe Broglie Wavelength Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree