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Question #44655

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The Question

At 300 K300 \text{ K}, the standard Gibbs free energy change for the gas-phase reaction: \ceN2(g)+3H2(g)<=>2NH3(g)\ce{N2(g) + 3H2(g) <=> 2NH3(g)} is ΔG∘=−11.49 kJ mol−1\Delta G^\circ = -11.49 \text{ kJ mol}^{-1} (Standard state: P∘=1 barP^\circ = 1 \text{ bar}). Let YY be the numerical value of the concentration-based equilibrium constant KcK_c (Standard state: c∘=1 mol L−1c^\circ = 1 \text{ mol L}^{-1}) for this reaction at 300 K300 \text{ K}.

Additionally, at 300 K300 \text{ K}, the ionic product of water is Kw=1.0×10−14K_w = 1.0 \times 10^{-14}. Let ΔGw∘\Delta G^\circ_w be the standard Gibbs free energy change for the autoionization reaction: \ceH2O(l)<=>H+(aq)+OH−(aq)\ce{H2O(l) <=> H+(aq) + OH-(aq)}

Which of the following correctly gives the values of YY and ΔGw∘\Delta G^\circ_w? (Given: R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1}, ln⁡10=2.303\ln 10 = 2.303, 1 bar=105 Pa1 \text{ bar} = 10^5 \text{ Pa}, 1 atm=101325 Pa1 \text{ atm} = 101325 \text{ Pa}, density of water ≈1 g mL−1\approx 1 \text{ g mL}^{-1})

Options

  • A.

    Y=6.22×104Y = 6.22 \times 10^4, ΔGw∘=80.42 kJ mol−1\Delta G^\circ_w = 80.42 \text{ kJ mol}^{-1}

  • B.

    Y=6.22×108Y = 6.22 \times 10^8, ΔGw∘=90.44 kJ mol−1\Delta G^\circ_w = 90.44 \text{ kJ mol}^{-1}

  • C.

    Y=6.06×104Y = 6.06 \times 10^4, ΔGw∘=80.42 kJ mol−1\Delta G^\circ_w = 80.42 \text{ kJ mol}^{-1}

  • D.

    Y=6.22×108Y = 6.22 \times 10^8, ΔGw∘=34.92 kJ mol−1\Delta G^\circ_w = 34.92 \text{ kJ mol}^{-1}

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Concepts Behind This Question

Dimensional Consistency of Constants|Relationship between Kp and Kc|Ionic Product of Water (Kw)

Why This Question Is Tricky

Common Mistakes

This problem tests the dimensional consistency of thermodynamic equilibrium constants and the definition of standard states.

Students often memorize Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n} without realizing that RR must carry units compatible with the standard states (P∘=1 barP^\circ = 1 \text{ bar}, c∘=1 mol L−1c^\circ = 1 \text{ mol L}^{-1}).

Using R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1} directly in this formula violates dimensional consistency.

Furthermore, the problem tests the standard state for pure liquids in heterogeneous equilibria; students frequently and incorrectly incorporate the concentration of water (55.5 M55.5 \text{ M}) into the thermodynamic equilibrium constant for autoionization, leading to an erroneous ΔGw∘\Delta G^\circ_w.

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Question Information

SubjectChemistry
ChapterSome Basic Concepts of Chemistry - Class 11 Part 1
ConceptDimensional Consistency of Constants
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree