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Question #44651

Difficulty: 8/10 | 🟢 Free

The Question

An analytical chemist is preparing a reaction mixture at 350 K350 \text{ K}. Exactly 25.00 mL25.00 \text{ mL} of an organic solvent is transferred at 350 K350 \text{ K} using a temperature-calibrated Class A volumetric pipette. According to the laboratory's standard operating procedure, the mass must be calculated using the experimentally measured density at the working temperature, which is 1.2 g/mL1.2 \text{ g/mL}. For reference, the literature density of the solvent at 298 K298 \text{ K} is 1.275 g/mL1.275 \text{ g/mL}, and its coefficient of thermal volume expansion is γ=1.10×10−3 K−1\gamma = 1.10 \times 10^{-3} \text{ K}^{-1}.

Calculate the mass of the solvent transferred at 350 K350 \text{ K}, reported to the correct number of significant figures.

Options

  • A.

    3.0×101 g3.0 \times 10^1 \text{ g}

  • B.

    30.00 g30.00 \text{ g}

  • C.

    30.15 g30.15 \text{ g}

  • D.

    30.05 g30.05 \text{ g}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Significant Figures in Arithmetic|Density-Volume-Mass Relationship

Why This Question Is Tricky

Common Mistakes

This problem tests the hierarchy of operations and significant figure rules in arithmetic.

Students are often tempted to use all provided data, falling into the trap of calculating the density at 350 K350 \text{ K} using the thermal expansion formula (dT2=dT1/(1+γΔT)d_{T2} = d_{T1} / (1 + \gamma \Delta T)) to obtain a highly precise density value (1.206 g/mL1.206 \text{ g/mL}, leading to 30.15 g30.15 \text{ g}).

However, the experimental density at 350 K350 \text{ K} is already provided with low precision (1.2 g/mL1.2 \text{ g/mL}).

In experimental chemistry, the precision of the final calculated value (mass) is strictly limited by the least precise measurement used in the calculation (density, 2 sig figs), regardless of the high precision of the volumetric glassware (4 sig figs).

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Question Information

SubjectChemistry
ChapterSome Basic Concepts of Chemistry - Class 11 Part 1
ConceptSignificant Figures in Arithmetic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree