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Question #44638
The Question
Consider the enantiomerically pure compound , -2-hydroxy-2-phenylpropanenitrile.
Experiment 1: is treated with 1 equivalent of in dry ether at 298 K, followed by mild aqueous workup to yield major product .
Experiment 2: is treated with excess in dry ether at 298 K, followed by aqueous workup to yield major product .
Identify the major products and .
Options
- A.
= Acetophenone; = -1-amino-2-phenylpropan-2-ol
- B.
= -3-hydroxy-3-phenylbutan-2-one; = -1-amino-2-phenylpropan-2-ol
- C.
= Acetophenone; = 1-phenylethan-1-ol
- D.
= -3-hydroxy-3-phenylbutan-2-one; = 1-phenylethan-1-ol
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Grignard Reagent Sensitivity|Reduction Selectivity (Hydrides)|Cyanohydrin Stereochemistry
Why This Question Is Tricky
Common Mistakes
This problem tests the hierarchy of Grignard reactivity (acid-base > nucleophilic addition) and the specific instability of cyanohydrin alkoxides.
Students often mechanically add the Grignard to the nitrile, forgetting the protic -OH group.
Furthermore, they miss that deprotonation of a cyanohydrin by a Grignard reagent leads to retro-cyanohydrin collapse (yielding a ketone), destroying the stereocenter.
Conversely, LiAlH4 coordinates the oxygen strongly, preventing collapse and allowing the reduction of the nitrile to a primary amine, preserving the chiral center.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Haloalkanes and Haloarenes - Class 12 |
| Concept | Grignard Reagent Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |