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Question #44634

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following reaction sequence:

1-bromo-4-(chloromethyl)benzene→dry acetone, ΔNaI (excess)Y\text{1-bromo-4-(chloromethyl)benzene} \xrightarrow[\text{dry acetone, } \Delta]{\text{NaI (excess)}} \text{Y}

Y→Mg (1 eq.), dry etherZ\text{Y} \xrightarrow{\text{Mg (1 eq.), dry ether}} \text{Z}

Z→2. H3O+1. CO2W\text{Z} \xrightarrow[\text{2. } H_3O^+]{\text{1. } CO_2} \text{W}

Identify the major product W.

Options

  • A.

    2-(4-bromophenyl)ethanoic acid

  • B.

    4-(chloromethyl)benzoic acid

  • C.

    2-(4-iodophenyl)ethanoic acid

  • D.

    4-(iodomethyl)benzoic acid

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Finkelstein and Swarts Exchange|Aryl Halide Resonance|Nucleophilic Aromatic Substitution (SNAr)

Why This Question Is Tricky

Common Mistakes

The core trap tests the student's ability to differentiate between the reactivity of alkyl/benzylic halides and aryl halides under SN2S_N2 conditions (Finkelstein reaction).

Students often blindly apply the reagent to the best leaving group (Br over Cl) without considering the structural context.

The aryl C−BrC-Br bond is unreactive due to resonance-induced partial double-bond character and the electron-rich π\pi-cloud repelling the nucleophile.

A secondary trap tests chemoselectivity in Grignard formation, where the weaker and more reactive benzylic C−IC-I bond reacts preferentially over the aryl C−BrC-Br bond.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptFinkelstein and Swarts Exchange
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree