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Question #44630

Difficulty: 8/10 | 🟢 Free

The Question

An organic compound \textbf{X}, 1-(2-bromopropyl)-2,4-dimethoxybenzene, is treated with Potassium fluoride (\ceKF\ce{KF}) and [2.2.2]cryptand in anhydrous benzene at 350 K350\text{ K}.

X+\ceKF→Benzene, 350 K[2.2.2]cryptandMajor Product (P)\textbf{X} + \ce{KF} \xrightarrow[\text{Benzene, } 350\text{ K}]{\text{[2.2.2]cryptand}} \text{Major Product (P)}

Identify the major product \textbf{P}.

Options

  • A.

    (E)-1-(2,4-dimethoxyphenyl)prop-1-ene

  • B.

    5,7-dimethoxy-2-methyl-2,3-dihydro-1H-indene

  • C.

    1-(2-fluoropropyl)-2,4-dimethoxybenzene

  • D.

    3-(2,4-dimethoxyphenyl)prop-1-ene

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

E1/E2 Solvent and Base Effects|Electrophilic Substitution Activation/Deactivation

Why This Question Is Tricky

Common Mistakes

The question tests the 'Naked Base' exception in elimination reactions.

Students typically learn that fluoride is a weak base and poor nucleophile due to strong hydrogen bonding in protic solvents.

The hidden variable is the use of a cryptand in a non-polar solvent, which strips the solvent shell and counterion, transforming F- into a superbase.

This forces an E2 elimination.

The primary trap is the intramolecular EAS pathway (Option B); students see a highly activated aromatic ring and an alkyl halide, mistakenly assuming a spontaneous Friedel-Crafts alkylation without realizing a Lewis acid is strictly required to generate the electrophile.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptE1/E2 Solvent and Base Effects
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree