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Question #44621
The Question
Consider the reaction of the following two bromo-ketones with 1 equivalent of in anhydrous DMF at 298 K:
Reaction 1:
Reaction 2:
Identify the correct IUPAC names for the major products and .
Options
- A.
is 2-ethyloxolane-2-carbonitrile; is 4,4,6,6-tetramethyl-5-oxoheptanenitrile
- B.
is 5-oxoheptanenitrile; is 4,4,6,6-tetramethyl-5-oxoheptanenitrile
- C.
is 2-ethyloxolane-2-carbonitrile; is 2-(tert-butyl)-3,3-dimethyloxolane-2-carbonitrile
- D.
is 5-oxoheptanenitrile; is 2-(tert-butyl)-3,3-dimethyloxolane-2-carbonitrile
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Steric Hindrance in SN2|Nucleophilic Addition Sterics
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to unify the concept of steric hindrance across different reaction mechanisms (Nucleophilic Addition vs.
SN2).
Students often memorize that 'cyanide does SN2 on primary halides' without considering the kinetically faster carbonyl addition followed by intramolecular cyclization.
The trap lies in recognizing that while the unhindered ketone (Reaction 1) successfully forms the cyclic ether via a tetrahedral alkoxide intermediate, the highly hindered di-tert-alkyl ketone (Reaction 2) completely blocks nucleophilic addition due to severe B-strain (back-strain) in the tetrahedral transition state.
This forces the reaction exclusively down the intermolecular SN2 pathway.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Haloalkanes and Haloarenes - Class 12 |
| Concept | Steric Hindrance in SN2 |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |