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Question #44612

Difficulty: 8/10 | 🟢 Free

The Question

Consider the reaction of (2-methoxypropan-2-yl)cyclobutane with 1 equivalent of anhydrous \ce{HI} at 298 K. Identify the major organic product formed.

Options

  • A.

    1-iodo-1,2-dimethylcyclopentane

  • B.

    (2-iodopropan-2-yl)cyclobutane

  • C.

    1-iodo-2,2-dimethylcyclopentane

  • D.

    2-cyclobutylpropan-2-ol and iodomethane

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

SN1 Carbocation Rearrangement|Ether Cleavage Patterns

Why This Question Is Tricky

Common Mistakes

This problem tests a multi-layered exception to standard ether cleavage rules.

The first trap is kinetic: students often default to SN2S_N2 cleavage for ethers with HI, predicting attack on the less hindered methyl group (Option D).

However, the presence of a tertiary carbon forces an SN1S_N1 pathway.

The second trap is thermodynamic: students who correctly identify the SN1S_N1 pathway might stop at the initial 3∘3^\circ carbocation (Option B).

The hidden variable is the ring strain of cyclobutane.

Advanced students must recognize that the relief of ring strain provides enough driving force to temporarily form a 2∘2^\circ carbocation from a 3∘3^\circ one.

The final trap is stopping after the ring expansion (Option C), failing to account for the subsequent 1,2-methyl shift that restores the carbocation to a 3∘3^\circ state before the halide attack.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptSN1 Carbocation Rearrangement
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree