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Question #44612
The Question
Consider the reaction of (2-methoxypropan-2-yl)cyclobutane with 1 equivalent of anhydrous \ce{HI} at 298 K. Identify the major organic product formed.
Options
- A.
1-iodo-1,2-dimethylcyclopentane
- B.
(2-iodopropan-2-yl)cyclobutane
- C.
1-iodo-2,2-dimethylcyclopentane
- D.
2-cyclobutylpropan-2-ol and iodomethane
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
SN1 Carbocation Rearrangement|Ether Cleavage Patterns
Why This Question Is Tricky
Common Mistakes
This problem tests a multi-layered exception to standard ether cleavage rules.
The first trap is kinetic: students often default to cleavage for ethers with HI, predicting attack on the less hindered methyl group (Option D).
However, the presence of a tertiary carbon forces an pathway.
The second trap is thermodynamic: students who correctly identify the pathway might stop at the initial carbocation (Option B).
The hidden variable is the ring strain of cyclobutane.
Advanced students must recognize that the relief of ring strain provides enough driving force to temporarily form a carbocation from a one.
The final trap is stopping after the ring expansion (Option C), failing to account for the subsequent 1,2-methyl shift that restores the carbocation to a state before the halide attack.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Haloalkanes and Haloarenes - Class 12 |
| Concept | SN1 Carbocation Rearrangement |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |