Start Learning Free

Before You Begin

Question #44555

Difficulty: 8/10 | 🟢 Free

The Question

Consider the synergic bonding in the following metal carbonyl complexes and their respective C-O bond lengths (dC−Od_{C-O}): (I) Terminal CO in \ce{[Mn(CO)6]+} (d1d_1) (II) Terminal CO in \ce{[Ni(CO)4]} (d2d_2) (III) μ2\mu_2-bridging CO in \ce{[Fe2(CO)9]} (d3d_3) (IV) Terminal CO in \ce{[Fe(CO)4]^{2-}} (d4d_4)

Which of the following options correctly identifies the increasing order of dC−Od_{C-O} and provides the accurate primary chemical reasoning for the species with the maximum bond length?

Options

  • A.

    d1<d2<d3<d4d_1 < d_2 < d_3 < d_4; Maximum dC−Od_{C-O} in (IV) is due to the highly negative formal charge on Fe (-2) maximizing dπ→π∗d\pi \rightarrow \pi^* back-donation, overcoming the typical dominance of μ2\mu_2-bridging denticity.

  • B.

    d1<d2<d4<d3d_1 < d_2 < d_4 < d_3; Maximum dC−Od_{C-O} in (III) is due to the μ2\mu_2-bridging CO accepting electron density from two metal centers simultaneously, which always exceeds back-donation into a terminal CO.

  • C.

    d2<d1<d3<d4d_2 < d_1 < d_3 < d_4; Maximum dC−Od_{C-O} in (IV) is due to the sp3sp^3 hybridization of Fe, which provides better directional overlap for synergic bonding compared to the d2sp3d^2sp^3 hybridization in (I).

  • D.

    d4<d3<d2<d1d_4 < d_3 < d_2 < d_1; Maximum dC−Od_{C-O} in (I) is due to the positive charge on Mn contracting its d-orbitals, forcing the CO ligand to expand its bond length to maintain orbital overlap.

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Ligand Denticity Variations|Synergic Bonding in Carbonyls|Variable Oxidation State Stability

Why This Question Is Tricky

Common Mistakes

This question tests the boundary between 'Ligand Denticity Variations' and 'Oxidation State Fluctuation'.

Students often memorize the heuristic that bridging carbonyls (μ2\mu_2, μ3\mu_3) always exhibit greater pi-back bonding (and thus longer C-O bonds) than terminal carbonyls.

The trap is Option B.

The 'Hidden Variable' is the extreme oxidation state of the metal.

The -2 formal charge on Fe in Collman's reagent (\ce{[Fe(CO)4]^{2-}}) creates an exceptionally electron-rich d10d^{10} center.

The magnitude of back-donation from this highly reduced mononuclear center into a terminal CO eclipses even the combined dual-metal back-donation into a μ2\mu_2-bridging CO in a neutral cluster like \ce{[Fe2(CO)9]}.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterCoordination Compounds - Class 12
ConceptLigand Denticity Variations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree