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Question #44544
The Question
A aqueous solution contains a total of of a mixture of two octahedral \ce{Co(III)} ammine complexes: a yellow complex and a green complex . Both complexes are synthesized exclusively from anhydrous \ce{CoCl3} and \ce{NH3}. The boiling point of this solution is at .
When excess \ce{AgNO3(aq)} is added to this solution, grams of \ce{AgCl(s)} precipitate is formed. Assuming ionization of the complexes and ideal behavior, what is the value of ?
(Given: for water = , Molar mass of \ce{AgCl} = , Boiling point of pure water = )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Van’t Hoff Factor (i) Application|Ammonolysis Complexity|Werner’s Theory Postulates
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Werner's Coordination Theory and Colligative Properties.
The 'Hidden Variable' is the mathematical relationship between the Van't Hoff factor and the number of ionizable counter-ions.
Students often get bogged down trying to identify the exact formulas of the yellow (luteo) and green (praseo) complexes and solving simultaneous equations.
The elegant exception/shortcut is realizing that for any mononuclear complex, the total moles of particles in solution is simply the sum of the moles of the complex itself and the moles of its dissociated counter-ions ().
Distractors trap students who confuse total chlorine atoms with ionizable chloride ions, or who miscalculate the Van't Hoff factor.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Solutions - Class 12 |
| Concept | Van’t Hoff Factor (i) Application |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |