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Question #44534
The Question
An alkene (\ce{3-methylbut-1-ene}) is subjected to hydroboration-oxidation using \ce{B2H6}/THF followed by alkaline \ce{H2O2} to yield a major organic product . Exactly of is completely converted to , and the entire yield of is dissolved in of benzene. The freezing point of the resulting solution is depressed by . Assuming undergoes partial dimerization in benzene due to intermolecular hydrogen bonding, identify the IUPAC name of and its percentage of dimerization. (Given: for benzene = , atomic masses: C=12, H=1, O=16)
Options
- A.
\text{3-Methylbutan-1-ol, } 40%
- B.
\text{2-Methylbutan-2-ol, } 40%
- C.
\text{3-Methylbutan-1-ol, } 20%
- D.
\text{2-Methylbutan-2-ol, } 20%
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Freezing Point Depression (Pure Solvent)|Hydroboration-Oxidation Regiochemistry|Degree of Dissociation/Association
Why This Question Is Tricky
Common Mistakes
This problem integrates organic synthesis with physical chemistry, testing two specific traps.
First, it tests the regiochemistry of hydroboration-oxidation.
Students who incorrectly assume a carbocation intermediate will predict a 1,2-hydride shift, leading to the tertiary alcohol \ce{2-methylbutan-2-ol}.
Second, it tests the colligative properties of associating solutes.
Alcohols in non-polar solvents like benzene undergo intermolecular hydrogen bonding, leading to dimerization.
Students who misapply the van't Hoff factor formula for association (e.g., using instead of ) will incorrectly calculate a 20% dimerization rate.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Solutions - Class 12 |
| Concept | Freezing Point Depression (Pure Solvent) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |