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Question #44532

Difficulty: 8/10 | 🟢 Free

The Question

A 2.665 g2.665 \text{ g} sample of a mixture containing two hydrate isomers of \ceCrCl3⋅6H2O\ce{CrCl3 \cdot 6H2O}, Isomer X (pale green) and Isomer Y (dark green), is dissolved in 100 g100 \text{ g} of water at 298 K298 \text{ K}. The boiling point of this solution is found to be 100.1456∘C100.1456^\circ\text{C} at 1 atm1 \text{ atm}. If the entire solution is treated with excess \ceAgNO3(aq)\ce{AgNO3(aq)}, what mass of \ceAgCl(s)\ce{AgCl(s)} will precipitate?

(Assume the boiling point of pure water is 100.000∘C100.000^\circ\text{C} at 1 atm1 \text{ atm}, 100%100\% ionization of the complex salts, ideal behavior, and no aquation of the inner coordination sphere. Given: Kb(\ceH2O)=0.52 K kg mol−1K_b(\ce{H2O}) = 0.52 \text{ K kg mol}^{-1}, Molar mass of \ceCrCl3⋅6H2O=266.5 g mol−1\ce{CrCl3 \cdot 6H2O} = 266.5 \text{ g mol}^{-1}, Molar mass of \ceAgCl=143.5 g mol−1\ce{AgCl} = 143.5 \text{ g mol}^{-1})

Options

  • A.

    2.583 g2.583 \text{ g}

  • B.

    4.305 g4.305 \text{ g}

  • C.

    4.018 g4.018 \text{ g}

  • D.

    2.153 g2.153 \text{ g}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Boiling Point Elevation (Solvent vs Solution)|Hydrate and Ionization Isomerism|Coordination Isomerism

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Coordination Chemistry (Hydrate/Ionization Isomerism) and Physical Chemistry (Colligative Properties).

The 'Hidden Variable' is the distinction between the Van't Hoff factor (ii) and the number of reactive chloride ions.

Students often fall into the trap of equating iavgi_{avg} directly to the moles of precipitatable \ceCl−\ce{Cl-} (Trap C) or ignoring the coordination sphere entirely to assume all chlorides are ionic (Trap B).

Success requires identifying the specific isomers from their standard colors (pale green vs dark green) to determine their primary and secondary valencies.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSolutions - Class 12
ConceptBoiling Point Elevation (Solvent vs Solution)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree