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Question #44487
The Question
The acidity of 1,3-cyclopentadiene (\ce{C5H6}) is governed by the formation of the aromatic cyclopentadienyl anion (\ce{C5H5^-}). However, its is highly solvent-dependent due to solvation effects. At 298 K, the of \ce{C5H6} is 15.0 in water and 18.0 in dimethyl sulfoxide (DMSO).
Given the following standard Gibbs free energies of transfer () from water to DMSO at 298 K:
Calculate the standard Gibbs free energy of transfer of the cyclopentadienyl anion, , from water to DMSO at 298 K. (Take )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Aromaticity (Huckel’s Rule)|Acidity and Basicity (pKa/pKb)|Basicity-Solvation Competition
Why This Question Is Tricky
Common Mistakes
The problem tests the thermodynamic cycle of acid dissociation across different solvents, highlighting the 'Basicity-Solvation Competition'.
While Huckel's rule explains the inherent stability of the cyclopentadienyl anion, its effective is heavily modulated by the solvent.
Students often assume polar aprotic solvents (like DMSO) uniformly destabilize all ions or fail to account for the fact that DMSO strongly solvates cations (like ) but poorly solvates anions due to the lack of hydrogen bonding.
The trap lies in correctly constructing the thermodynamic cycle and applying the correct signs for the transfer free energies, particularly recognizing that the transfer of the non-polar is exergonic, while the transfer of the anion is highly endergonic.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Hydrocarbons - Class 11 Part 2 |
| Concept | Aromaticity (Huckel’s Rule) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |