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Question #44434

Difficulty: 8/10 | 🟢 Free

The Question

An optically active cyclic diol, (1R,2R,4R,5S)-4,5-dimethylcyclohexane-1,2-diol, is subjected to oxidative cleavage using an excess of periodic acid (\ceHIO4\ce{HIO4}) in aqueous methanol at 298 K. Which of the following correctly describes the stereochemistry and optical activity of the major organic product?

Options

  • A.

    Optically inactive \textit{meso}-(3R,4S)-3,4-dimethylhexanedial

  • B.

    Optically active (3R,4R)-3,4-dimethylhexanedial

  • C.

    Optically active (3S,4S)-3,4-dimethylhexanedial

  • D.

    Racemic mixture of (3R,4R) and (3S,4S)-3,4-dimethylhexanedial

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Glycol Periodic Acid Cleavage|Optical Activity and Enantiomers

Why This Question Is Tricky

Common Mistakes

This problem tests the 'conservation of optical activity' fallacy.

Students often incorrectly assume that reactions of chiral molecules that do not directly break bonds at the stereocenters will always yield chiral products.

Here, the oxidative cleavage destroys the asymmetry of the ring, revealing a hidden plane of symmetry in the open-chain product and converting a chiral glycol into an achiral meso dicarbonyl.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAlcohols, Phenols, and Ethers - Class 12
ConceptGlycol Periodic Acid Cleavage
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree