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Question #44428
The Question
Compound is 5-hydroxy-2,2-dimethylhexanal. is subjected to two separate reaction sequences:
- is treated with excess Tollens' reagent at 298 K, followed by careful acidification to yield the major organic product .
- is treated with excess at 298 K, followed by careful acidification to yield the major organic product .
Which of the following correctly identifies and ?
Options
- A.
is 5-hydroxy-2,2-dimethylhexanoic acid; is 2,2-dimethylpentanedioic acid.
- B.
is 2,2-dimethyl-5-oxohexanoic acid; is 2,2-dimethylpentanedioic acid.
- C.
is 5-hydroxy-2,2-dimethylhexanoic acid; is 4,4-dimethyl-5-oxopentanoic acid.
- D.
is 5-hydroxy-2,2-dimethylhexanoic acid; is 2,2-dimethyl-5-oxohexanoic acid.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Iodoform Reaction Requirements|Tollens vs. Fehling Specificity
Why This Question Is Tricky
Common Mistakes
This question tests 'Functional Group Interference' and the specific oxidizing capabilities of diagnostic reagents.
A common student trap is assuming that only acts as a test for methyl ketones or secondary alcohols, forgetting that hypohalites are strong enough to oxidize aldehydes to carboxylic acids (eliminating Option C).
Another trap is failing to recognize that the secondary alcohol is first oxidized to a methyl ketone before undergoing the iodoform cleavage (eliminating Option D), or incorrectly assuming Tollens' reagent is strong enough to oxidize secondary alcohols (eliminating Option B).
The absence of -hydrogens adjacent to the aldehyde in prevents competing aldol or -halogenation side reactions, ensuring a clean transformation.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Alcohols, Phenols, and Ethers - Class 12 |
| Concept | Iodoform Reaction Requirements |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |