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Question #44409

Difficulty: 8/10 | 🟢 Free

The Question

Consider the specific stereoisomer of 2-amino-5-(tert-butyl)-1-phenylcyclohexan-1-ol where, in its most stable chair conformation, the \textit{tert}-butyl, phenyl, and amino groups are all equatorial, and the hydroxyl group is axial. This compound is treated with \ce{NaNO2} and aqueous \ce{HCl} at 273 K273\text{ K}. Identify the major organic product formed.

Options

  • A.

    (3-(tert-butyl)cyclopentyl)(phenyl)methanone

  • B.

    5-(tert-butyl)-2-phenylcyclohexan-1-one

  • C.

    4-(tert-butyl)-2-phenylcyclohexan-1-one

  • D.

    5-(tert-butyl)-1-phenylcyclohex-1-ene

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Pinacol-Pinacolone Rearrangement|Optical Isomerism Logic

Why This Question Is Tricky

Common Mistakes

This question tests the supremacy of Stereoelectronic Control over inherent Migratory Aptitude in rigid cyclic systems.

A common trap for students is to blindly apply the rule that 'Phenyl has a higher migratory aptitude than alkyl groups' and incorrectly predict phenyl migration (which would yield 5-(tert-butyl)-2-phenylcyclohexan-1-one).

However, in the semi-pinacol rearrangement, the transition state requires the migrating group to be anti-periplanar to the leaving group.

Because the diazonium leaving group is equatorial, the anti-periplanar group is the adjacent C-C ring bond, forcing a ring contraction regardless of the phenyl group's higher electronic migratory aptitude.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAlcohols, Phenols, and Ethers - Class 12
ConceptPinacol-Pinacolone Rearrangement
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree