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Question #44359

Difficulty: 8/10 | 🟢 Free

The Question

Compound X\textbf{X} is \ce{methyl 2-(2-bromophenyl)acetate}. It is subjected to two distinct reaction pathways to test functional group compatibility and reactive intermediates:

\textbf{Pathway A:} X\textbf{X} is treated with excess \ce{NaNH2} in liquid \ce{NH3} at 240 K240\text{ K}, followed by careful neutralization, to yield the major product P\textbf{P}.

\textbf{Pathway B:} X\textbf{X} is first treated with excess \ce{LiAlH4} in dry THF at 298 K298\text{ K} followed by aqueous workup to give intermediate Y\textbf{Y}. Y\textbf{Y} is then treated with excess \ce{NaNH2} in liquid \ce{NH3} at 240 K240\text{ K}, followed by neutralization, to yield the major product Q\textbf{Q}.

Identify the structures of P\textbf{P} and Q\textbf{Q}.

Options

  • A.

    P\textbf{P} = Indolin-2-one; Q\textbf{Q} = 2,3-Dihydrobenzofuran

  • B.

    P\textbf{P} = 2-(2-Aminophenyl)acetamide; Q\textbf{Q} = 2-(2-Aminophenyl)ethanol

  • C.

    P\textbf{P} = Indoline; Q\textbf{Q} = Benzofuran

  • D.

    P\textbf{P} = 2,3-Dihydrobenzofuran; Q\textbf{Q} = Indolin-2-one

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Benzyne Intermediate (Elimination-Addition)|Reduction Selectivity (Hydrides)|Aryl Halide Resonance

Why This Question Is Tricky

Common Mistakes

The 'Hidden Variable' being tested is the chemoselective transformation of the ester group and its dictation of the intramolecular nucleophile's identity.

Students often memorize that NaNH2 forms benzyne, but overlook that it also rapidly converts esters to amides via ammonolysis.

By forcing a choice between direct base treatment (Pathway A) and prior hydride reduction (Pathway B), the problem tests whether the student recognizes that reducing the carbonyl 'destroys' the potential to form a nitrogen heterocycle, replacing it with an oxygen heterocycle.

Distractors exploit the assumption of intermolecular attack (Option B) or incorrect oxidation states of the heterocycles (Option C).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptBenzyne Intermediate (Elimination-Addition)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree