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Question #44349

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following reaction sequence:

Naphthalen-2-ol→120 ∘C, 4-7 atm1. \ceNaOH,CO2 2. \ceH3O+X (Major Product)\text{Naphthalen-2-ol} \xrightarrow[\text{120 }^\circ\text{C, 4-7 atm}]{\text{1. } \ce{NaOH, CO2} \text{ 2. } \ce{H3O+}} \textbf{X} \text{ (Major Product)}

X→pH = 9-10, 0-5 ∘C\cePh−N2+Cl−Y (Major Product)\textbf{X} \xrightarrow[\text{pH = 9-10, 0-5 }^\circ\text{C}]{\ce{Ph-N2+ Cl-}} \textbf{Y} \text{ (Major Product)}

Identify \textbf{X} and \textbf{Y}.

Options

  • A.

    X\textbf{X} = 2-Hydroxynaphthalene-1-carboxylic acid; Y\textbf{Y} = 1-(Phenyldiazenyl)naphthalen-2-ol

  • B.

    X\textbf{X} = 2-Hydroxynaphthalene-1-carboxylic acid; Y\textbf{Y} = 6-(Phenyldiazenyl)-2-hydroxynaphthalene-1-carboxylic acid

  • C.

    X\textbf{X} = 3-Hydroxynaphthalene-2-carboxylic acid; Y\textbf{Y} = 1-(Phenyldiazenyl)-3-hydroxynaphthalene-2-carboxylic acid

  • D.

    X\textbf{X} = 3-Hydroxynaphthalene-2-carboxylic acid; Y\textbf{Y} = 4-(Phenyldiazenyl)-3-hydroxynaphthalene-2-carboxylic acid

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Electrophilic Substitution Activation/Deactivation|Azo Coupling Regioselectivity

Why This Question Is Tricky

Common Mistakes

This question tests two critical exceptions in electrophilic aromatic substitution.

First, the temperature-dependent regioselectivity of the Kolbe-Schmitt reaction on 2-naphthol (Kinetic vs Thermodynamic control).

Second, the 'hidden' ipso-substitution in azo coupling.

Students typically assume that if the most reactive position (C1) is blocked by a substituent, the electrophile will attack the next available position (e.g., C6).

However, because the carboxyl group is an excellent leaving group (as \ceCO2\ce{CO2}) and the C1 position is overwhelmingly activated, the diazonium ion attacks the ipso position, displacing the carboxyl group entirely.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptElectrophilic Substitution Activation/Deactivation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree