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Question #44349
The Question
Consider the following reaction sequence:
Identify \textbf{X} and \textbf{Y}.
Options
- A.
= 2-Hydroxynaphthalene-1-carboxylic acid; = 1-(Phenyldiazenyl)naphthalen-2-ol
- B.
= 2-Hydroxynaphthalene-1-carboxylic acid; = 6-(Phenyldiazenyl)-2-hydroxynaphthalene-1-carboxylic acid
- C.
= 3-Hydroxynaphthalene-2-carboxylic acid; = 1-(Phenyldiazenyl)-3-hydroxynaphthalene-2-carboxylic acid
- D.
= 3-Hydroxynaphthalene-2-carboxylic acid; = 4-(Phenyldiazenyl)-3-hydroxynaphthalene-2-carboxylic acid
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Electrophilic Substitution Activation/Deactivation|Azo Coupling Regioselectivity
Why This Question Is Tricky
Common Mistakes
This question tests two critical exceptions in electrophilic aromatic substitution.
First, the temperature-dependent regioselectivity of the Kolbe-Schmitt reaction on 2-naphthol (Kinetic vs Thermodynamic control).
Second, the 'hidden' ipso-substitution in azo coupling.
Students typically assume that if the most reactive position (C1) is blocked by a substituent, the electrophile will attack the next available position (e.g., C6).
However, because the carboxyl group is an excellent leaving group (as ) and the C1 position is overwhelmingly activated, the diazonium ion attacks the ipso position, displacing the carboxyl group entirely.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Haloalkanes and Haloarenes - Class 12 |
| Concept | Electrophilic Substitution Activation/Deactivation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |