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Question #44338
The Question
An unstable blue-colored complex is formed when an acidified aqueous solution of is treated with . To stabilize , the reaction is extracted into an organic solvent like diethyl ether. Upon standing in the aqueous acidic medium, spontaneously undergoes an internal redox decomposition to yield a green solution of , along with the evolution of a diatomic gas and water.
Determine the correct tuple , where: Oxidation state of the central metal in . Formal charge on the central metal in the most stable Lewis structure of (minimizing formal charge, assuming all bonds are covalent). Number of moles of gas evolved per mole of completely decomposed.
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Formal Charge Calculation|Electron Transfer Accounting|KMnO₄ Redox pH Dependency
Why This Question Is Tricky
Common Mistakes
This question tests the critical distinction between Oxidation State (redox bookkeeping assuming ionic bonds) and Formal Charge (Lewis bookkeeping assuming covalent bonds).
Students frequently fall into the trap of calculating the OS of Cr as by ignoring the peroxy linkages, or assigning a non-zero FC by misapplying the octet rule to a transition metal.
Furthermore, the decomposition of is a complex internal redox reaction.
A common trap is assuming all peroxy oxygens convert to (yielding ), failing to balance the electron transfer where some must reduce to to satisfy the requirement of the reduction.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Formal Charge Calculation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |