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Question #44335

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following reaction sequence starting from (2S)(2S)-2-iodo-3,3-dimethylbutane (Compound \textbf{X}):

X→Δ\ceCH3ONa (1.0 M),\ceCH3OHY (Major Product)\textbf{X} \xrightarrow[\Delta]{\ce{CH3ONa} \text{ (1.0 M)}, \ce{CH3OH}} \textbf{Y} \text{ (Major Product)} Y→\ceHBr,\ceR2O2,hνZ (Major Product)\textbf{Y} \xrightarrow{\ce{HBr}, \ce{R2O2}, h\nu} \textbf{Z} \text{ (Major Product)} Z→\ceNaSCH3,\ceDMF,298 KW (Major Product)\textbf{Z} \xrightarrow{\ce{NaSCH3}, \ce{DMF}, 298\text{ K}} \textbf{W} \text{ (Major Product)}

Identify the major product \textbf{W}.

Options

  • A.

    1-(methylthio)-3,3-dimethylbutane

  • B.

    2-(methylthio)-2,3-dimethylbutane

  • C.

    2-(methylthio)-3,3-dimethylbutane

  • D.

    2,3-dimethyl-2-butene

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Fajans' Rule Polarization Power|C-X Bond Polarization and Polarizability|Steric Hindrance in SN2

Why This Question Is Tricky

Common Mistakes

The problem tests the boundary between electronic polarizability and steric hindrance.

While polarizability suggests the C-I bond is primed for SN2, the extreme steric bulk of the adjacent tert-butyl group completely blocks the SN2 trajectory, forcing an E2 pathway.

Furthermore, it traps students who assume an E1 carbocation rearrangement (prevented by the strong base) or a 1,2-alkyl shift during the radical addition (radicals do not rearrange like carbocations).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Bonding and Molecular Structure - Class 11 Part 1
ConceptFajans' Rule Polarization Power
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree